1. Невозможно создать два конструктора, если оба имеют одинаковый тип переменных в качестве аргументов.
Или для этого нужно переопределение?
2. Компилятор сообщает об отсутствии ";" В коробке 73, но вот она;
package com.javarush.task.task06.task0621;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
/*
Родственные связи кошек
*/
public class Solution {
public static void main(String[] args) throws IOException {
BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
String grandPapaName = reader.readLine();
Cat catGradPa = new Cat(grandPapaName);
String grandMamName = reader.readLine();
Cat catGradMa = new Cat(grandMamName);
String fatherName = reader.readLine();
Cat catFather = new Cat(fatherName,grandPapaName );
String motherName = reader.readLine();
Cat catMother = new Cat(motherName, grandMamName);
String somName = reader.readLine();
Cat catSon = new Cat(somName, catMother, catFather);
String daughterName = reader.readLine();
Cat catDaughter = new Cat(daughterName, catMother, catFather);
System.out.println(catGradPa);
System.out.println(catGradMa);
System.out.println(catFather);
System.out.println(catMother);
System.out.println(catSon);
System.out.println(catDaughter);
}
public static class Cat {
private String name;
private Cat parent;
private Cat parent2;
Cat(String name) {
this.name = name;
}
Cat(String name, Cat parent){
this.name = name;
this.parent = parent;
}
Cat(String name, Cat parent2){
this.name = name;
this.parent2 = parent2;
}
Cat(String name, Cat parent, Cat parent2) {
this.name = name;
this.parent = parent;
this.parent2 = parent2;
}
@Override
public String toString() {
if (parent == null && parent2 == null)
return "The cat's name is " + name + ", no mother, no father ";
else if(parent == null && parent2 != null)
return "The cat's name is " + name + ", no mother , father is" +parent2.name);
else if(parent != null && parent2 == null)
return "The cat's name is " + name + ", mother is " + parent.name + ", no father ");
else
return "The cat's name is " + name + ", mother is " + parent.name + ", father is" +parent2.name);
}
}
}